Question

If a ball is thrown straight up into the air with an initial velocity of 60 ft/s, it height in feet after t second is given by y=60t−16t2. Find the average velocity for the time period begining when t=2 and lasting
(i) 0.1 seconds

(ii) 0.01 seconds

(iii) 0.001 seconds

Answer 1

INTEGRATE IT/LASTING TIME

Answer 2

i tried it says it's a wrong answer

Answer 3

INTEGRATING FROM 2 TO 2.1/0.1

Answer 4

i did 100 time it shows me wrong answer

Answer 5

OPTIONS

Answer 6

0.1=26.8 and 2=28 and it shows wrong

Answer 7

5.6

Answer 8

FOR A

Answer 9

0.1=5.6?

Answer 10

IAM SORRY
DONT INTEGRATE
AVG VEL=TOTAL DISTANCE/TOTAL TIME

Answer 11

SO Y(2.1)-Y(2)/0.1
WILL BE THE ANSWER

Answer 12

IS IT FINE

Answer 13

58.8?

Answer 14

i tried 28 i didn't work