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if u = -x and du = -dx, why is integral -b to -a f(u)du = integral -b to -a f(x)dx ?
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Well I think you only can do this: \[\displaystyle\int_{-b}^{-a}f(u)du=-\displaystyle\int_{b}^{a}f(-x)dx\\(u=-x\longrightarrow du=-dx)\]
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