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X2-6X-7=0
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ax^2+bx+C=0 Have this : We have two answer there X1and X2 (1,2are just name of answers .) And to find them : -b+_Delta(under Radical)/2a Delta=b^2-4ac Got it ?:)
@IBRAHIM2009
u have to solve it by the forrmula
Yea ! Right :)
i hope u know the formula.it must be present in ur text book.
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I said that :) Look at to up please :)
quadratic formula=\[x=-b \pm \sqrt{b^2 -4ac}\div2a\] here a=1 b=-6 c=-7 hence by applying formula we get two roots which are 7 and -1
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