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Mathematics 16 Online
OpenStudy (anonymous):

HELP!?!

OpenStudy (anonymous):

\[1/x2+5x+6+1/x+3\]

OpenStudy (anonymous):

what to do?

OpenStudy (anonymous):

Add and simplify ^^

OpenStudy (anonymous):

@giligails

OpenStudy (anonymous):

add terms having same power of x

OpenStudy (anonymous):

1 --- x+2 2 ---------- (x+2)(x+3) x+2 ---------- (x+2)(x+3 those are the answers

OpenStudy (anonymous):

\[x^{-2}+x^{-1}+5x+9\] is this your equation

OpenStudy (anonymous):

x^2+5x+6=(x+2)(x+3) now take1/(x+3) do lcm and add

OpenStudy (anonymous):

1/(x+3)[1+x+2]/(x+2) (x+3)/[(x+3)(x+2)] 1/(x+2)

OpenStudy (anonymous):

thxx!

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