How do i find the x and y components of the vectors A⃗ and B⃗??? this is the other info: Vector A⃗ , in the first quadrant, has a magnitude |A⃗ |= 2.0 and is at an angle α = 40 ∘ with respect to the positive x-axis. Vector B⃗ , in the fourth quadrant, has a magnitude |B⃗ |= 1.5 and is at an angle β = 20.0 ∘ with respect to the positive x-axis.
so the best way to do this I feel for an explanation is to draw a picture
|dw:1379446473118:dw|
we are starting with A because it is easier
so if you look at that line you can see the magnitude and you can see how far to reaches out and this you can turn into a right triangle
|dw:1379446581908:dw|
so after that you can use trig values of sin and cos to find the components
you can do the same thing with B, but remember it is in quadrant 4 so your values are different since By is negative
|dw:1379446740234:dw|
Join our real-time social learning platform and learn together with your friends!