Question

8-(3+b)=b-9

Answer 1

First you need to distribute the negative into the parentheses on the left side. 8 - 3 - b = b - 9 Now, put the b one one side, add one b to the right side --> 8 - 3 = 2b -9 Solve from there! Hope this helped!

Answer 2

\[8 - \left( 3 + b \right) = b - 9\]
\[8 - 3 - b = b - 9\]
\[5 + 9 = b + b\]
\[14 = 2b\]
\[\frac{ 14 }{ 2 } = \frac{ 2b }{ 2 }\]
\[b = 7\]

Answer 3

if you substitute b with 7 in your equation you will find that your LHS=RHS