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Mathematics 21 Online
OpenStudy (anonymous):

(6-p)^2 36-12p+p^2 = ?

OpenStudy (anonymous):

\[(6-p)^{2}36-12p+p ^{2}\]

OpenStudy (anonymous):

are you kidding me @pokemon23 ? I asked how do i do it? Not different ways to solve the problem

OpenStudy (anonymous):

It's such an easy algebraic problem. I'm confused on one of the steps.

OpenStudy (pokemon23):

Then tell me where are you getting confused?

OpenStudy (pokemon23):

Start with the beginning

OpenStudy (anonymous):

\[(6-p)(6-p)36-12p+p ^{2} \] \[6^{2}-2(6)(p)+p ^{2}\] \[36-12p+p ^{2}(36-12p+p ^{2})\] the last part is the confusion. @pokemon23

OpenStudy (anonymous):

@SlightlyConfused the website Pokemon23 gave you will give you the answer

OpenStudy (pokemon23):

I got you slightly confused

OpenStudy (pokemon23):

just don't call me stupid in chat

OpenStudy (anonymous):

haha!:D

OpenStudy (anonymous):

you're confused too @pokemon23 ??????? lol

OpenStudy (pokemon23):

No

OpenStudy (pokemon23):

I'm actually going to write a pargraph

OpenStudy (pokemon23):

fine

OpenStudy (pokemon23):

so we must distribute the 36

OpenStudy (pokemon23):

what do you get

OpenStudy (anonymous):

It's okay if you don't know the answer

OpenStudy (anonymous):

1296

OpenStudy (anonymous):

Is this what you needed help with so badly????

OpenStudy (anonymous):

Yes lacey omg

OpenStudy (pokemon23):

I'm actually guiding you the answer

OpenStudy (anonymous):

It would be better if you gave me the answer @pokemon23

OpenStudy (anonymous):

No giving away answers.

OpenStudy (anonymous):

LACEY COME ON

OpenStudy (anonymous):

What is between 2 and 36?

OpenStudy (anonymous):

@SlightlyConfused

OpenStudy (pokemon23):

|dw:1379457070255:dw|

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