Mathematics
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OpenStudy (anonymous):
(6-p)^2 36-12p+p^2 = ?
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OpenStudy (anonymous):
\[(6-p)^{2}36-12p+p ^{2}\]
OpenStudy (anonymous):
are you kidding me @pokemon23 ? I asked how do i do it? Not different ways to solve the problem
OpenStudy (anonymous):
It's such an easy algebraic problem. I'm confused on one of the steps.
OpenStudy (pokemon23):
Then tell me where are you getting confused?
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OpenStudy (pokemon23):
Start with the beginning
OpenStudy (anonymous):
\[(6-p)(6-p)36-12p+p ^{2} \]
\[6^{2}-2(6)(p)+p ^{2}\]
\[36-12p+p ^{2}(36-12p+p ^{2})\]
the last part is the confusion. @pokemon23
OpenStudy (anonymous):
@SlightlyConfused the website Pokemon23 gave you will give you the answer
OpenStudy (pokemon23):
I got you slightly confused
OpenStudy (pokemon23):
just don't call me stupid in chat
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OpenStudy (anonymous):
haha!:D
OpenStudy (anonymous):
you're confused too @pokemon23 ??????? lol
OpenStudy (pokemon23):
No
OpenStudy (pokemon23):
I'm actually going to write a pargraph
OpenStudy (pokemon23):
fine
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OpenStudy (pokemon23):
so we must distribute the 36
OpenStudy (pokemon23):
what do you get
OpenStudy (anonymous):
It's okay if you don't know the answer
OpenStudy (anonymous):
1296
OpenStudy (anonymous):
Is this what you needed help with so badly????
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OpenStudy (anonymous):
Yes lacey omg
OpenStudy (pokemon23):
I'm actually guiding you the answer
OpenStudy (anonymous):
It would be better if you gave me the answer @pokemon23
OpenStudy (anonymous):
No giving away answers.
OpenStudy (anonymous):
LACEY COME ON
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OpenStudy (anonymous):
What is between 2 and 36?
OpenStudy (anonymous):
@SlightlyConfused
OpenStudy (pokemon23):
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