The table below shows two equations:

Equation 1 |3x – 1| + 7 = 2
Equation 2 |2x + 1| + 4 = 3

Which statement is true about the solution to the two equations?
Equation 1 and equation 2 have no solutions.

Equation 1 has no solution and equation 2 has solutions x = 0, 1.

The solutions to equation 1 are x = -1.3, 2 and equation 2 has no solution.

The solutions to equation 1 are x = -1.3, 2 and equation 2 has solutions x = 0, 1.

Question

The table below shows two equations:


Equation 1	|3x – 1| + 7 = 2
Equation 2	|2x + 1| + 4 = 3


Which statement is true about the solution to the two equations?
 Equation 1 and equation 2 have no solutions.

 Equation 1 has no solution and equation 2 has solutions x = 0, 1.

 The solutions to equation 1 are x = -1.3, 2 and equation 2 has no solution.

 The solutions to equation 1 are x = -1.3, 2 and equation 2 has solutions x = 0, 1.

anonymous · Answer

they have no solutions since abolute value of 3x-1 and abs of 2x-1 is going to be a positive number because its all about magnitude

tkhunny · Answer

These are both eyeball problems.  Just write the answer down about as fast as you can read the problem statement.

2 - 7 < 0
3 - 4 < 0
|stuff| >= 0

No solutions.

anonymous · Answer

thank you!