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Help please The acute angle x radians is such that tanx=k, where k is a positive constant. Express in terms of k... i) tan(pi-x) ii) tan (1/2pi-x) iii)sinx
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2
tan (pi/2 - x) = tanx
property
But the answers 1/k for part two
oh , u need to evaluate , huh?
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okay...
1) tan(pi-x) = -tanx = -k 2)
tan(pi/2 - x) = tan(90degrees - x) = cotx = 1/k
tan(pi-x) i think is the answer
sinx / cosx = tanx sinx = tanx * cosx = kcosx
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gottit ?
Sweet cheers man, appreciate it
no probs , mate !!
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