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OpenStudy (anonymous):
find the limit as x approaches 0 of sin 9x/x
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OpenStudy (blockcolder):
\[\lim_{x\to0}\frac{\sin{9x}}{x}=\lim_{x\to0}\frac{\sin{9x}}{9x}\cdot 9=9\lim_{x\to0}\frac{\sin{9x}}{9x}=9\lim_{u\to0}\frac{\sin{u}}{u}\]
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