What is the equation of the line that passes through(-10,8) and (5,5)?
fine the slope of the line and then apply two point form...
Ive tried everything but i keep getting B and idk why
What am i doing wrong?
Find their slope using rise/run. Use any of the points then. And use the point-slope of the line then you'll get your answer. Point-slope form = (y-y1) = m(x-x1) Where m is slope (x1,y1) is any of the 2 points given to you. Understood? :)
slope = y2-y1 / x2-x1 and one point form is y- y1= slope(x-x1)
Im confused...
y-8 = -3/15 (x+10) what eq u will get after solving it...
u will get 15y - 120 = -3x-30 divide the equation by three.. so u will get 5y - 40 = -x-10 transfer all terms to one side... you will get.. x+5y-30 which is equal to A
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