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What is the equation of the line in point-slope form that passes through the given point and has the given slope? point; (8,-8) and slope;3
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y - y1 = m(x - x1) m, your slope is 3 (8,-8) x1 = 8 and y1 = -8 now what can you do with that ?
just sub in your info into the formula
okay and then what?
that is your answer.
I got y-8=3(x-8) is that right?
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\(\bf (x_1,y_1) \implies (8, -8)\\\large \\\quad \\ \begin{array}{llll} (&\bf 8, &\bf -8)\\ y-&\bf y_1=m(x-&\bf x_1) \end{array}\)
ahemm... even ... wrong there.. shoot
pay attention to the signs.. y - (-8) = 3(x - 8) which is : y + 8 = 3(x - 8)
\(\bf (x_1,y_1) \implies (8, -8)\\\large \\\quad \\ \begin{array}{llll} (&\bf -8, &\bf 8)\\ y-&\bf y_1=m(x-&\bf x_1) \end{array}\)
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