Question

Miguel leaves by automobil at 9:00 A.M. and stops for repairs at 9:20 A.M. If the distance covered was 18 miles, what was the average velocity, in miles per hour for this part of the trip?

Answer 1

20 minutes = 1/3 hour

Answer 2

\(\large \text{Average velocity} = \frac{\text{displacement}}{\text{time}}\)

Answer 3

\(\large \text{Average velocity} = \frac{\text{18 miles }}{\text{1/3 hour}}\)

Answer 4

simplify

Answer 5

Oh thanks :)

Answer 6

np :)