Question

Solve for x in terms of a:
11x^4-122a^2x^2=-11a^4

Answer 1

rewrite the equation

\[11x^4 - 122x^2a^2 + 11a^4 = 0\]

the equation can be factored

11 is a prime number... so factors are 11 and 1

the middle term is negative and last term positive so the binomial factors have a negative operator

the middle term also contains a^2 and x^2... so that means you have x^2 and a^2 in the binomials.


\[11x^4 - 122x^2a^2 + 11a^4 =(11x^2 - a^2)(x^2 - 11a^2)\]

now you can solve for x in terms of a