Question

Solve the following system of equations using elimination:
3x + 5y = 12
2x + 8y = 22


A. (-1, 3)
B. (1, -3)
C. (1, 3)
D. (3, -1)

Answer 1

@Luis_Rivera @John_ES @jim_thompson5910

Answer 2

Again, multiply the first row by 2 and the second by -3,
\[\begin{cases}6x+10y=24\\
-6x-24y=-66\end{cases}\] Sum the equations
\[-14y=-42\Rightarrow y=3\]Now use the substitution in the first equation, for example, and you will obtain x=-1. So you have (-1,3)

Answer 3

Thanks John!! :D

Answer 4

;)

Answer 5

@Luis_Rivera, you use a wrong system, the y is not in your solution.