Question

Solve the following system of equations using elimination:
13x + 5y = 16
2x - 8y = 20


A. (-2, -3)
B. (-2, 2)
C. (2, -2)
D. (2, 2)

Answer 1

These systems grow like flowers in the field. :)
You must multiply the first by 8 and the second by 5,
\[\begin{cases}104x+40y=128\\
10x-40y=100\end{cases}\]And sum both equations,
\[114x=228\Rightarrow x=2\]Now you can susbtitute this value in the second equation and obtains for y, y=-2. So you have (2,-2)

Answer 2

C