Question

Solve the system, using substitution.
3a - b = 11 and 2a + 3b = 0


A. (3, 2)
B. (3, -2)
C. (-3, 2)
D. (-3, -2)
E. no solution

Answer 1

Using the second,
\[a=-3b/2\]Plug into the second,
\[3(-3b/2)-b=11\Rightarrow -9b/2-b=11\Rightarrow -11b/2=11\Rightarrow b=-2\]Using again, the first equation,
\[a=3\]

Answer 2

thaaaaank yo

Answer 3

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