Question

This might be a physics question too, but I thought I'd put it here first:
Seth starts from a rest at the end of his driveway and accelerates down the road at 0.40 m/sec^2 for 12 seconds. What is his speed at the end of 12 seconds?

Answer 1

please, really need help ):

Answer 2

you have formula to calculate a , it says \(a = \dfrac{v-v_0}{t}\) the car starts at rest means \(v_0=0\) so, \(v =at = 0.40*12= 4.8m/s\)

Answer 3

Bless. you.

Answer 4

ty