A man invested $22,500, some at 7% and some at 10% annual interest. The annual income from these investments was $2,130. How much did he invest at each rate?

Question

anonymous · Answer

It's a system of equations.  Can you create the system?

anonymous · Answer

The accounts are represented by $x$ and $y$.

anonymous · Answer

$$x+y=\dots$$

anonymous · Answer

"A man invested $22,500"$$
x+y=22500
$$

anonymous · Answer

"some at 7% and some at 10% annual interest. The annual income from these investments was $2,130."

Try to create an equation with this.

Hint:  The equation should contain $0.07x$ and $0.10y$.

***[isuru]*** · Answer

Hi, 
 This is just my opinion,
          I think there is an easier way to solve this
 if u take the amount man invested at 7% interest is x then the amount he invest at 10% is      (22 500 - x )

   Then,
       as his profit is 2130
  there will be a single equation like this
    
    7x/100 + 10(22500 - x)100 = 2130

   u can solve this for x and get the amount he invest at 7% in one shot and the u could  use that value get other amount