Mathematics
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OpenStudy (anonymous):
Please help me!
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OpenStudy (anonymous):
Already know answer for 15 & 16
OpenStudy (anonymous):
which question
OpenStudy (anonymous):
all but 15 & 16 please
OpenStudy (anonymous):
In 15 :
BC + CE = BE
Now answer :)
OpenStudy (anonymous):
I already know 15 & 16!
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OpenStudy (anonymous):
Ahaa !
OK !
Another ????
OpenStudy (anonymous):
Yeah can you see the rest? need help with 17-22 please :D
OpenStudy (anonymous):
17:BC = CD
OpenStudy (anonymous):
the figure showed it
OpenStudy (anonymous):
BC + CD = ?
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OpenStudy (anonymous):
for 17 it says shove for X i did
3x+2=5x-10
x2=12
x=6
am i right?
OpenStudy (anonymous):
yes :)
OpenStudy (anonymous):
okay for 18 i got 4
OpenStudy (anonymous):
yep !
OpenStudy (anonymous):
okay 19 im not sure, help? :D
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OpenStudy (anonymous):
yep !
OpenStudy (anonymous):
Thank you ! :D can you explain it to me also?
OpenStudy (anonymous):
which one?19?
OpenStudy (anonymous):
Explane what ?:)
OpenStudy (anonymous):
Yes! how you got the answer and 19
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OpenStudy (anonymous):
answer for 17 & 18 ?
OpenStudy (anonymous):
no 19
OpenStudy (anonymous):
for 17 i got x=6 and for 18 i got 4, we are working on 19
OpenStudy (anonymous):
well,first say the mesure of BC
OpenStudy (anonymous):
19 : Look we have 60 and if both are 60 we have : 60+60=120
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OpenStudy (anonymous):
no,we can't say both are 60
OpenStudy (anonymous):
Your first answer for 17 was right :)
OpenStudy (anonymous):
if you look at the file i posted it shows a graph thingy next to wquestion 15 & 16 it needs be based off of that
OpenStudy (anonymous):
we can :)
My mean was that s 60 .
OpenStudy (anonymous):
prove...
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OpenStudy (anonymous):
No no your last answer s are right :)
OpenStudy (anonymous):
it needs be base off of this, see?
OpenStudy (anonymous):
for questions 15-20 it needs to be from that thing i just posted
OpenStudy (anonymous):
I think one of our is enogh ...
If u need me riplay :)
thank u :)
OpenStudy (anonymous):
So for 19 what would we do?
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OpenStudy (anonymous):
oh,first i think we can find BC and CF...can you find them?
OpenStudy (anonymous):
oh the line graph thingy?
OpenStudy (anonymous):
there is probably sth wrong with the question 19...
OpenStudy (anonymous):
why?
OpenStudy (anonymous):
on the thing i posted we need to find GCA and BCA.......... BCG is 60......
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OpenStudy (anonymous):
it must give us the mesure of GCA !
OpenStudy (anonymous):
No... we have to find GCA AND BCA!!!
OpenStudy (anonymous):
i think we can't find any rule to solve it...we only know that angle BCG is 60!
OpenStudy (anonymous):
okay lets go next one
OpenStudy (anonymous):
yes,i'll think about 19 later :)
20:
|dw:1379642412147:dw|
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OpenStudy (anonymous):
we need to use this!!
OpenStudy (anonymous):
ok i know!i just draw it to make a better understanding...
OpenStudy (anonymous):
angleACD - angleHCD = angleACH
ok?
OpenStudy (anonymous):
Oh okay sorry sir!
OpenStudy (anonymous):
ok
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OpenStudy (anonymous):
its ACD DCH and HCA
OpenStudy (anonymous):
no problem :);)
so 60 - 20 = 40
:)
angle ACH = 40
OpenStudy (anonymous):
there no such thing as ACH its HCA
OpenStudy (anonymous):
there's no difference between ACH and HCA darli :)
OpenStudy (anonymous):
@tesla117 :Where is your question ?
Need my help ??
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OpenStudy (anonymous):
quesiton 19 and oh ok sir
OpenStudy (anonymous):
ok,it's not an important thing to say :D
OpenStudy (anonymous):
no prob :) so we solved question 20 too
OpenStudy (anonymous):
so for HCA is 40? thats my answer?
OpenStudy (anonymous):
and need help on question 21?
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OpenStudy (anonymous):
yes i explained it...
OpenStudy (anonymous):
no problem :);)
so 60 - 20 = 40
:)
angle ACH = 40