Mathematics
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OpenStudy (anonymous):
How do I solve (sqrt)2x+3 = x ?
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hartnn (hartnn):
its \(\sqrt{2x+3}=x\)
right ?
square both sides ,what u get ?
OpenStudy (anonymous):
2x +3 = x^2 ?
OpenStudy (anonymous):
Then I solve from there?
hartnn (hartnn):
yes, you know how to solve that quadratic equation ?
OpenStudy (anonymous):
I'm not sure..
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OpenStudy (anonymous):
It looks easy! I don't know what I'm missing..
hartnn (hartnn):
we have x^2-2x-3 =0
ok ?
can you tell me 2 numbers whose sum is -2 and product is -3 ??
hartnn (hartnn):
hint : one number is positive and other is negative
OpenStudy (anonymous):
-3 times 1?
hartnn (hartnn):
correct!
so we split the -2x into -3x+1x
we have now
x^2-2x+x-3 =0
know how to proceed further ?
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OpenStudy (anonymous):
combine like terms?
hartnn (hartnn):
factor out 'x' from the 1st 2 terms
x^2-2x
what u get ?
OpenStudy (anonymous):
wait, I don't understand. What are we doing with the x's?
hartnn (hartnn):
we are trying to factor
x^2-2x-3=0
and get and answer like (x-a)(x+b) = 0
OpenStudy (anonymous):
would it be 0 = (x-3)(x+1) ?
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hartnn (hartnn):
correct! good :)
hartnn (hartnn):
(x-3)(x+1) = 0
so
x-3=0 , x = .... ?
x+1 =0, x= ... ?
hartnn (hartnn):
correct! good :)
OpenStudy (anonymous):
x=3 and x=-1
OpenStudy (anonymous):
Thank you so much! I should have known this. I appreciate it. (:
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hartnn (hartnn):
you are most welcome ^_^