Question

factor completely 3u^2-33u+72

Answer 1

Good place to start is to factor out a 3. If you know what I mean and how to do that.

Answer 2

3(u^2-11u+24) ?

Answer 3

3(u^2-11u+24)
3(u^2-(8+3)u+24) [8+3 = 11, 8*3=24]
3(u^2-8u-3u+24)
3(u(u-8)-3(u-8))
3(u-8)(u-3)

Understood? :)

Answer 4

Nvm then, lol.

Answer 5

thank you

Answer 6

:)

Answer 7

can you help me with another one? (4x^2+28x-36)