Find the area of the window outlined by semicircular regions
@jdoe0001 how do doth is right here?
sorryf or the typo my computer is glitching badly
you keep asking the same question over and over again?
http://openstudy.com/users/ash90#/updates/523b4a84e4b00182897e9980 http://openstudy.com/users/ash90#/updates/523b521ae4b00182897e9cdf
|dw:1379621210629:dw|
got your Rs transposed
@amistre64 an d you don't answer my question
ohhh smokes, man hehehe
the first link I provided shows that I DO answer ...
|dw:1379621482162:dw|
is 2441664 what you got?
hmmm... what were those units there? I can see 180cm but the other is... 900? inches?
or is it 61725.612
hmm.... well 180cm is 1.8 meters 900m is 90000 cm how can the INNER diameter of 90000cm be smaller than the OUTER diameter which is 180cm?
can... you post a quick screenshot of the material?
i did it wrong then
ahemm, is 90 cm, no 900m :|
so, the radius for each, will be HALF-THAT recall radius is \(\bf \cfrac{diameter}{2}\) so |dw:1379625987133:dw|
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