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Let (theta) be an angle in quadrant 2 such that cos(theta) = -4/5 . Find the exact values of csc(theta) and tan(theta)
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just draw a triangle in the quadrant |dw:1379629101307:dw| then you can find csc and tan
Awesome, almost had this but posted it just incase. I got \[\csc \theta\] = 5/3 and \[\tan \theta\] = -3/4
yep... thats it
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