Question

A coin is tossed 3 times. The possible outcomes are:
HHH, HTH, HHT, HTT, TTT, TTH, THH, THT
How do I find the possibilities of each???

Answer 1

the outcome of each of these is equal so what you have to do is divide 100 by 8
and that would be the probability percentage

Answer 2

i would think so

Answer 3

there are 8 outcomes...

P(event) = number of favourable/total number

just write them as fractions

Answer 4

1/8?

Answer 5

i guess

Answer 6

thats correct... for each of the listed events... as they are equally likely

Answer 7

12.5% for each of them

Answer 8

yeah i think thats it