can someone help in this question A company has a security system comprising four electronic devices (A, B, C and D) which operate independently. Each device has a probability of 0.1 of failure. The four electronic devices are arranged so that the whole system operates if at least one of A or B functions and at least one of C or D functions. Show that the probability that the whole system functions properly is 0.9801. we have use probability tree need help test tomorrow please
|dw:1379672044728:dw| The probability tree applies to each pair of devices, A and B, C and D. The probability of one or both devices of a pair operates is given by 0.81 + 0.09 + 0.09 = 0.99 The probability that one or both devices in A and B, C and D operate (that is the probability that the whole system functions properly) is given by 0.99 * 0.99 = 0.9801
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