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solve: 2xyy'=y^2 +xy
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that isn't right this is calculus
or implicit differentiation
Yes implicit differentiation is used to find tangents on equations that are not functions (fail vertical line test) It has been so long since I have done such problems it is hard for me to remember how to go about them
actually this may not be implicit differentiation.
The equation can be arragnge to the form dy/dx = f(y/x) apply the subsitution y/x = v y = vx dy/dx = v'x+v v'x+v = f(v)
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this will now be variables seperable
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