Question

Please explain to me why my maths is wrong here

Find Q
log(Q)-log(Q/(Q+1))=0.8
log(Q/(Q/Q+1))=0.8
log(Q+1)=0.8
10^0.8=Q+1
Q=5.309

Answer 1

nothing wrong here

Answer 2

yup, wolfram gives the same answer

http://www.wolframalpha.com/input/?i=log%28Q%29-log%28Q%2F%28Q%2B1%29%29%3D0.8&a=*FunClash.log-_*Log10-

Answer 3

btw, its assumed that

log = log_10

Answer 4

and you dont mean log_e = ln

Answer 5

Thats odd becaus when I put it into wolfram then it gives me 1.22

Answer 6

lol i got 1.22 aswell,

then i noticed that wolfram used natural logarthm (base e)
I had to change it to base 10


here is wat u wud have seen :-
http://www.wolframalpha.com/input/?i=log%28Q%29-log%28Q%2F%28Q%2B1%29%29%3D0.8&a=*FunClash.log-_*Log-

Answer 7

ahhh thanks yea that explains it. I thought I was going mad that I couldnt work out such a simple equation.

Answer 8

happens sometimes.. ;)