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Solve: -10=3y-5(y-2) 10 4 -10 -4
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-10=3y-5y+10 -10-10=3y-5y now solve for y...can u do it?
have u undrstood how have i done?....the brackt term will be multiplied by 5
-20=-2y minus gets cancelled, y=20/2 y=10
Yes I understood that thank you :)
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-10=3y-5(y-2) distribute the -5 -10=3y-5y+10 Add like terms -10=-2y +10 transpose 10 -10 -10 = -2y -20=-2y Divide both sides by -2 to get y y=10 :)
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