Question

can someone continue the process,

log(base 7) (x -5) + log (base 7 ) x + 1 = 1

log base 7 ( x-5)( x+1) = 1

7 = x^2 -4x -5

what now ?

Answer 1

x^2-4x-5-7=0
x^2-4x-12=0
factorise it now

Answer 2

we have the same thought, but take a look at this..

x^2 -4x = 12

(x+2) = 12 , (x-6) = 12

Answer 3

x^2-(6-2)x-12=0
can u do it now?

Answer 4

can you explain further? especially the (6-2) x

Answer 5

x^2-6sx+2x-12=0
x(x-6)+2(x-6)=0
(x+2)(x-6)=0
now,x=-2 or 6

Answer 6

Thank you , instead of factoring by grouping I can equat it to zero right?

Answer 7

use the process jst i did its easier.have u unrdrstood the entire process?

Answer 8

Yes :)

Answer 9

Thanks :)

Answer 10

welcome