8. Solve for x: 4(x−3)+2x=3(2x−5)

A. x = 0
B. x = all real numbers
C. x = 6
D. there is no solution

Question

8. Solve for x: 4(x−3)+2x=3(2x−5)


A.	x = 0
B.	x = all real numbers
C.	x = 6
D.	there is no solution

anonymous · Answer

do you know how to distribute through the parenthesis ?

anonymous · Answer

you take the number or sign right before the parenthesis and multiply it by everything in the parenthesis.

4(x - 3) + 2x = 3(2x - 5)
4x - 12 + 2x = 6x - 15 -- combine like terms
6x - 12 = 6x - 15 -- add 12 to both sides
6x = 6x - 15 + 12 -- combine like terms
6x = 6x - 3 -- subtract 6x from both sides
0 = -3 -- incorrect
There is no solution

any questions ?