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ASAP a basketball player standing under the hoop shoots the ball straight up with an initial velocity of v=3.5 from 2.5m above the ground. What is the max height, above the launch point the basketball will achieve? a formula provided would be nice.
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vf^2=vi^2 +2gh <----- is that the right equation for this problem?
s=ut + 1/2at^2 and here a=g with a minus sign as ball is retarding
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