Question

Simplify completely: the quantity 14 times x to the 5th power times y to the 4th power plus 21 times x to the third power times y to the 2nd power all over 7 times x to the third power times y

Answer 1

\[ \frac{14x^5 y^4 + 21x^3 y^2}{7x^3y} \]
?

Answer 2

you can write the problem like this
\[ \frac{14x^5 y^4 + 21x^3 y^2}{7x^3y} \\
\frac{14x^5 y^4}{7x^3y}+ \frac{ 21x^3 y^2}{7x^3y}
\]

Answer 3

can you simplify the numbers part? what is 14/7 ?
what is 21/7 ?