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Help me factor?
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\[3x ^{2}+31x+36\]
(Using the X method please)
never heard of the X method
the way i'd do it is 3 * 36 = 108 now find 2 factors of 108 which add up to 31
what do you think the 2 factors are?
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I thought it was 27 and 4 but the correct answer is \[(3x+4)(x+9)\]
What I don't understand is how to get that answer
3x^2 + 31x + 36 = 3x^2 + 27x + 4x + 36 this can be factored by grouping = 3x(x + 9) + 4(x + 9) = (3x + 4)(x + 9
last line should be (3x + 4)(x + 9)
follow that ok?
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