Question

Need help with c programming

Answer 1

ask i will help

Answer 2

concerning what be specific also

Answer 3

I am writing a code which takes in hex values and double values and uses it in a formula

Answer 4

and the answer should b in hex

Answer 5

I know how to scan a hex number and use in the formula. The only problem I am having is how can I convert the decimal value into hex

Answer 6

any idea?

Answer 7

try this one

char * double2HexString(double a)
{
char *buf = new char[17]; // double is 8-byte long, so we have 2*8 + terminating \0
char *d2c;
d2c = (char *) &a;
char *n = buf;
int i;
for(i = 0; i < 8; i++)
{
sprintf(n, "%02X", *d2c++);
n += 2;
}
*(n) = '\0';
}

also declare the library

Answer 8

hm..I see you are using looping but we are told not to!! I don't know why. It is a very basic program. We have not started using arrays yet.

Answer 9

anyways, thank you !. I will try to do something else.

Answer 10

ok

Answer 11

Here's a recursive function for converting decimal to any base up to 36:

#include <stdio.h>
#include <stdlib.h>

int mkDigit( int number, int base, char* answer )
{
char characters[37] = { "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ" };
int remainder, index;

if( number == 0 )
return( 0 );

remainder = number % base;
number /= base;

index = mkDigit( number, base, answer );
answer[ index ] = characters[ remainder ];
return( ++index );
}