Question

2^3-3*5-8=1 insert grouping symbols to make a true statement

Answer 1

\[2^3-3\times 5-8=-15\] (not 1)
so
\[(2^3 = 8) (-3\times5 = -15) (-8 = -8) =15 \]
so try
\[2^3-3\times(5-8)= 8 - (3\times-3)= 8-9 = -1\]
hmm close but still not it
maybe
\[2^{(3-3)\times(5-8)}= 2^{(0)\times(-3)} = 2^0 = 1\]
bingo!