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Mathematics 12 Online
OpenStudy (happykiddo):

|x-2|+2 < 3

OpenStudy (anonymous):

|dw:1379820965318:dw|

OpenStudy (anonymous):

note there are numerous ways to do this

OpenStudy (happykiddo):

what about the +2 outside the absolute value symbols

OpenStudy (anonymous):

do you understand how i obtained |x-2|<1

OpenStudy (anonymous):

that 2 was subtracted from 3 on right side of equatin

OpenStudy (happykiddo):

yeah i gotchya now thanks : )

OpenStudy (anonymous):

yw

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