An electron is projected horizontally at a speed of 1.21E+7m/s into an electric field. The field exerts a constant, vertically oriented force of 4.22E-16N on the particle. Determine the vertical distance by which the electron is deflected in the amount of time needed for it to have moved 28.0mm horizontally.

Question

anonymous · Answer

You should find time t by using x=v*t  

Then, find the vertical acceleration by  using F=m*a 

You can get the vertical distance by putting t and a into  y=(a*t^2)/2