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Mathematics 9 Online
OpenStudy (anonymous):

x2-11x+24=0

OpenStudy (yamyam70):

what is your question ?

OpenStudy (anonymous):

how to solve this equation

OpenStudy (yamyam70):

are finding the value for all x ?

OpenStudy (anonymous):

just solve the following equation

OpenStudy (yamyam70):

factor the left hand side first.

OpenStudy (yamyam70):

IN open study we just don't give out answers. please do take time to read the code of conduct.. found here http://openstudy.com/code-of-conduct

OpenStudy (anonymous):

can u give the first step

OpenStudy (yamyam70):

\[x^2-11x +24 =0\] I believe this is your given

OpenStudy (anonymous):

yes

OpenStudy (yamyam70):

Factor out the left hand side which is x^2−11x+24

OpenStudy (yamyam70):

that is the first step

OpenStudy (anonymous):

x2=35 is this the answer

OpenStudy (yamyam70):

nope

OpenStudy (yamyam70):

we are solving for all value of x right? is that the question?

hero (hero):

\[x^2 - 11x + 24 = 0\]\[x^2 -(3 + 8)x + 24 = 0\]\[x^2 - 3x - 8x + 24 = 0\]\[x(x-3)-8(x-3) = 0\]\[(x-3)(x-8) = 0\] You should be able to finish solving for x from here @ashiq

OpenStudy (anonymous):

thx hero

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