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OpenStudy (yamyam70):
that is the first step
OpenStudy (anonymous):
x2=35 is this the answer
OpenStudy (yamyam70):
nope
OpenStudy (yamyam70):
we are solving for all value of x right? is that the question?
hero (hero):
\[x^2 - 11x + 24 = 0\]\[x^2 -(3 + 8)x + 24 = 0\]\[x^2 - 3x - 8x + 24 = 0\]\[x(x-3)-8(x-3) = 0\]\[(x-3)(x-8) = 0\]
You should be able to finish solving for x from here @ashiq
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