Question

Write the equation of the line with a slope of -5 and a y-intercept of (0,3).

Write the equation of the line with a slope of -1/3 and passing through the point (6, -4).

Write the equation of the line passing through the points (0, -4) and (-2, 2).

Write the equation of the line passing through the points (-6,1) and (-4,2).

Write the equation of the line with an undefined slope, passing through the point (2, 5).

Answer 1

im so stuck

Answer 2

can anyone help please

Answer 3

slope of -5 and y intercept of (0,3)
y = -5x + 3
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point slope formula : y - y1 = m(x - x1)
slope(m) = -1/3
(6,-4) x1 = 6 and y1 = -4
sub it in
y - (-4) = -1/3(x - 6)
y + 4 = -1/3x + 2
y = -1/3x + 2 - 4
y = -1/3x -2
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slope formula : m = (y2 - y1) / (x2 - x1)
(0,-4) x1 = 0 and y1 = -4
(-2,2) x1 = -2 and y1 = 2
sub it in
m = (2 - (-4) / (-2 - 0)
m = (2 + 4) / -2
m = 6/-2
m = -3

point slope formula :
y - y1 = m(x - x1)
slope(m) = -3
(-2,2) x1 = -2 and y1 = 2
sub it in
y - 2 = -3(x - (-2)
y - 2 = -3(x + 2)
y - 2 = -3x - 6
y = -3x - 6 + 2
y = -3x - 4
=================
slope formula : m = (y2 - y1) / (x2 - x1)
(-6,1) x1 = -6 and y1 = 1
(-4,2) x2 = -4 and y2 = 2
sub it in
m = (2 - 1) / (-4,- (-6)
m = 1/ (-4 + 6)
m = 1/2

y - y1 = m(x - x1)
slope(m) = 1/2
(-6,1) x1 = -6 and y1 = 1
sub it in
y - 1 = 1/2(x - (-6)
y - 1 = 1/2(x + 6)
y - 1 = 1/2x + 3
y = 1/2x + 3 + 1
y = 1/2x + 4
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Undefined slope means that the slope is divided by 0. There is no " run ". It is a vertical line. If it passes through (2,5), then the equation is x = 2
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any questions ?