Question

Find an equation of the tangent line to the curve
y = 8x sin x at the point (π/2, 4π).
y'=8(sinx)+8xcosx
8(sinπ)+8π(cosπ)
0+(-8π)
not sure what to do after that.

Answer 1

why did u plug in x = pi ?
x=pi/2 right ??
(pi/2,4pi)