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Find an equation of the tangent line to the curve at the given point. y = 4e^x cos x, (0, 4) y'=4
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ok... it appears that you have the slope at the point (0, 4) so you just need to find the equation of the tangent then slope intercept form is y = mx + b or in your question y = 4x + b substitute x = 0 and y = 4 to find the value of b, and the equation of your line
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