In the olympic shot-put event, an athlete throws the shot with an initial speed of 12.0 m/s at a 40 degree angle from the horizontal. the shot leaves her hand at a height of 1.80 m above the ground
how far does the shot travel

Question

In the olympic shot-put event, an athlete throws the shot with an initial speed of 12.0 m/s at a 40 degree angle from the horizontal. the shot leaves her hand at a height of 1.80 m above the ground
how far does the shot travel

anonymous · Answer

Range = V x sin(2xTHETA)/9.8 = 12x sin(2x40)/9.8 = 1.2m

anonymous · Answer

but i just noticed its 1.8m above ground..