Question

let f(x)= sin (2x) give the value of lim as h approaches 0; f(h) - f (0)/h

Answer 1

are you asking for \[\lim_{h \rightarrow 0}(\sin2h-\sin0)/h\] ?

Answer 2

We Know the fact that \[\lim_{x \rightarrow 0}\frac{ \sin x }{ x } = 1\]
to use this equation, transform formulus.
\[\lim_{h \rightarrow 0}\frac{ \sin 2h }{2h } * 2 \]
now, you result in solution.