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Find the volume of the solid obtained by rotating the region bound by the given curves about the specified line. y=8x^3 y=0 x=1 about x=2 Please Help!
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We have: |dw:1379913498099:dw|
So then, if we move \(f(x)=8x^3\) over a unit to the left to become g(x) like so: \(g(x)=8(x+1)^3\), then we can simplify the problem to one about revolving the function g(x) about the y-axis!
|dw:1379913466327:dw| h = f(x) = 8x^3 r = x+1
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