Question

1) Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line.
y=6sinx, y=6cosx 0<=x<=pi/4 about y=-1

i got pi integral (1+6cosx)^2 - (1+sinx)^2 dx from 0 to pi/4

then as my answer i got pi(29/4 +7sqrt2+35pi/8)

it says its wrong but not sure why.

2) find the volume of V of the solid obtained by rotating the region bound by the given curves about the specified line.

y=x, y=0, x=3 x=5 about x=1

If you can give me any direction on number 2 i would really appreciate it.

Answer 1

@dumbcow
These are the last 2 I need help on :) please and thank you

Answer 2

ok i looked at your work for 1st one and everything looks good...what is original function
"sin x" or "6sin x" ??

Answer 3

6sin x

Answer 4

yeah thats why then...you had typo in your post "sin x" so adjust integral to include "6sin x"

Answer 5

ohhh so its
\[6+12\sqrt{2}\]

Answer 6

#2 doesnt seem that bad...graph it out

Answer 7

its the little mistakes that always get me

Answer 8

I didnt think number 2 was but maybe bc of the others im over thinking it haha