Question

#include int main(){ int a=2; a=a++ + ~++a; printf("%d",a); return 0; } The output to this prog is 0. Can anyone explain to me how the prog flows? The first think that will happen is the preincremnt term is solved.. a++ + ~3.. What happens next?

Answer 1

@Callisto

Answer 2

@DLS

Answer 3

@DLS

Answer 4

o teri,merko to ek bhi notification nahi ayi

Answer 5

use chod. answer bta.. JALDI

Answer 6

#include<stdio.h>
int main(){
int a=2;
a=a++ + ~++a;
printf("%d",a);
return 0;
}

The output to this prog is 0. Can anyone explain to me how the prog flows?
The first think that will happen is the preincremnt term is solved.. a++ + ~3..
What happens next?

------------------------------
a=2 hai
a++ + ++a hota to..
2 + 4 = 6 hota ab bitwise compliment tu dekhle.

Answer 7

a ko sahi evaluate kiya hai na tune?

Answer 8

haan. ~3=-4 abhi prog bnake dekha maine.
chad. dekhi jayegi. :/

Answer 9

ho gya. kal btata hun.

Answer 10

okay,badiya