A mass hangs on the end of a massless rope. The pendulum is held horizontal and released from rest. When the mass reaches the bottom of its path it is moving at a speed v = 2.3 m/s and the tension in the rope is T = 22.5 N.
How long is the rope?
What is the mass?
If the maximum mass that can be used before the rope breaks is mmax = 1.74 kg, what is the maximum tension the rope can withstand? (Assuming that the mass is still released from the horizontal.)
Now a peg is placed 4/5 of the way down the pendulum’s path so that when the mass falls to its vertical position it hits and wraps around t

Question

A mass hangs on the end of a massless rope. The pendulum is held horizontal and released from rest. When the mass reaches the bottom of its path it is moving at a speed v = 2.3 m/s and the tension in the rope is T = 22.5 N. 
How long is the rope?
What is the mass?
If the maximum mass that can be used before the rope breaks is mmax = 1.74 kg, what is the maximum tension the rope can withstand? (Assuming that the mass is still released from the horizontal.) 
Now a peg is placed 4/5 of the way down the pendulum’s path so that when the mass falls to its vertical position it hits and wraps around t