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Algebra 15 Online
OpenStudy (anonymous):

factor (x+3)^2-(x+3)-56 completely.

OpenStudy (anonymous):

do the parentheses first

OpenStudy (anonymous):

or you can subsitute u = x+3 look at u^2 - u - 56 factor that - then put back the x+3 for the u

OpenStudy (anonymous):

either way the answer is the same. so post what you got...

OpenStudy (anonymous):

so would it be (u+7)(u-8) then replacing u with the (x+3) the answer should be (x+3+7)(x-3-8) ?

OpenStudy (anonymous):

yes, now combing the numbers to simply - note the second set you put in x-3 getting (x+10) (x-5)

OpenStudy (anonymous):

oops I meant combining...

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