Given: PA is tangent to the circle with center O.
Prove: triangle APB is similar to triangle CPA.

A, B, and C are points on the circle. P is outside the circle.

Question

Given: PA is tangent to the circle with center O.
Prove: triangle APB is similar to triangle CPA.


A, B, and C are points on the circle. P is outside the circle.

anonymous · Answer

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directrix · Answer

Given: PA is tangent to the circle with center O.
   Prove: triangle APB is similar to triangle CPA.

Statements

1. Segment PA is tangent to the circle with center O.
2. m<CAP = (1/2)* m Arc AC
3. m<B = (1/2) * m Arc AC
4. <CAP ≅ < B
5.< P ≅ <P
6.  Triangle APB ~ Triangle CPA

directrix · Answer

@kleduff87   Your task is to complete the reasons. Post what you get. Okay?